Subject: Re: [xsl] XPath 1.0 challenge: select all XML Schema element declarations with type string From: "Ihe Onwuka ihe.onwuka@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sun, 19 Jul 2015 20:29:15 -0000 |
On Sun, Jul 19, 2015 at 4:26 PM, liam liam@xxxxxx < xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > On 2015-07-19 15:58, Costello, Roger L. costello@xxxxxxxxx wrote: > >> Hi Folks, >> >> The following XPath expression returns all XML Schema element >> declarations with @type equal to xs:string: >> >> //xs:element[@type = 'xs:string'] >> >> However, that XPath assumes the schema file is written with a >> namespace prefix, like this: >> >> <xs:element name="Test" type="xs:string" /> >> > > But the schema file could have been written like this: >> >> <element name="Test" type="string" /> >> > > There are two issues here. The first is matching the element called > 'element' and your XPath expression will work fine there, assuming you've > bound the prefix "xs" to the XML Schema namespace URI and that the same > namespace name is the default namespace for the prefix-less Schema document. > > The second issues is matching "string" or xs:string". We know that it's a > QName and must have zero or one colon, so > @type = "string" or substring-after(@type, ":") = "string" > would work. > > Ahhhhh Good spot on the 2nd issue Liam.
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