Subject: Re: [xsl] CALS to XHTML table - rowspan From: "Kraetke, Martin, le-tex martin.kraetke@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 6 Oct 2015 13:37:35 -0000 |
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:css="http://www.w3.org/1996/css" xmlns:hub="http://docbook.org/ns/docbook" xmlns:dbk="http://docbook.org/ns/docbook" xmlns:saxon="http://saxon.sf.net/" xmlns:tr="http://www.transpect.io" xmlns:calstable="http://docs.oasis-open.org/ns/oasis-exchange/table" version="2.0">
<!-- Documentation: in normalize.xsl --> <xsl:import href="normalize.xsl"/>
<xsl:template match="node() | @*" > <xsl:copy copy-namespaces="no"> <xsl:apply-templates select="@*, node()"/> </xsl:copy> </xsl:template>
<xsl:template match="*[*:row]"> <xsl:sequence select="calstable:check-normalized( calstable:normalize(.), 'no' )"/> </xsl:template>
Hello:
It has been a while since I worked on XSLT. But I have a current issue that I need to solve with xslt.
I have a CALS table that has @morerows. I have to generate a table that does not have a rowspan attribute, and generate cells according to the value of @morerows.
So, my input XML looks like this:
<table> <tgroup> <tbody> <row><entry morerows="2">test 1</entry> <entry morerows="1">test 2</entry> <entry morerows="0">test 3</entry> </row> <row><entry morerows="0">test 4</entry> <entry morerows="1">test 5</entry> <entry morerows="0">test 6</entry> </row> </tbody> </tgroup> </table>
How do I generate rows/cells based on morerows in xslt?
Any tips is appreciated.
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