Subject: Re: [xsl] Need Math Help: How to Convert Proportional Column Widths to Real Values? From: "a kusa akusa8@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 29 Dec 2015 18:18:33 -0000 |
Hello: I was looking to do something similar and found this question. In my case, I don't have the total table column width always. So, if I have a mixed col width values of 1.38,1.38.1*,1.38, how can I find the real value for 1*? Thanks in advance for all suggestions. On Fri, Mar 7, 2014 at 6:10 PM, Liam R E Quin <liam@xxxxxx> wrote: > On Fri, 2014-03-07 at 17:51 -0600, Eliot Kimber wrote: > >> For example, say that I have two proportional columns of width "1*" and >> "1.39*" and the available width is 240pt. >> >> How do I determine fraction of 240 each of these proportions get? > > 1. add up the proportional values; call that Peter. > 2. subtract any fixed-width columns from the available width to get > whatever remaineth; call that Wendy. > 3. each column has width in proportion, so that a column with width 1.38 > has actual width of Wendy C 1.38 divided by Peter. > (you could call them ProportionalTotal and WidthAvailable rather than > Peter and Wendy if you wanted I suppose.) > > -- > Liam Quin - XML Activity Lead, W3C, http://www.w3.org/People/Quin/ > Pictures from old books: http://fromoldbooks.org/ > Ankh: irc.sorcery.net irc.gnome.org freenode/#xml
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