Subject: [xsl] Following-sibling - question From: "a kusa akusa8@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 6 Jan 2016 14:31:23 -0000 |
Hello: I am trying to write some code to find the next X number of following sibling elements and I am a little stuck. My input XML file is a table: <table> <tbody> <row> <entry>1</entry> </entry>2</entry> </row> <row> <entry>3</entry> </entry>2</entry> </row> <row> <entry>4</entry> </entry>2</entry> </row> <row> <entry>5</entry> </entry>2</entry> </entry>2</entry> </row> <row> <entry>6</entry> </row> </tbody> </table> My desired output is: <table> <tbody> <row> <entry>1</entry> </entry>2</entry> </row> <row> <entry>want entry here - 1.1</entry> <entry>3</entry> </entry>2</entry> </row> <row> <entry>4</entry> <entry>want an entry here - 3.1 </entry> </entry>7</entry> </row> <row> <entry>5</entry> </entry>2</entry> </entry>2</entry> <entry>want an entry here - 7.1</entry> </row> <row> <entry>6</entry> </row> </tbody> </table> So, I want to write logic to say that for the next n where n=3 in this example - rows, add an entry element I tried to calculate the next n rows based on current(), but it is not working. Any suggestion is appreciated. Thank you in advance for your help.
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