Re: [xsl] XPath expression which checks that a string is between 1 and 10 characters in length?

["Eliot Kimber ekimber@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

How about:

if (string(.) != '') then string-length(.) le 10 else false()

That requires casting the context to a string twice but calculating string-length() once.

Or 

matches(., '..?.?.?.?.?.?.?.?')

(Can I do that with '..?{0,10}'? Reviewing the syntax it looked like the quantifier could only be a single digit.)

Cheers,

Eliot

> On July 26, 2016 at 7:01 AM "Wolfgang Laun wolfgang.laun@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> 
> 
> Just for fun:
> 
> string-length() idiv 2 le 5
> 
> Optimization by obfuscation. Phooey.
> -W
> 
> On 26 July 2016 at 13:55, Martin Honnen martin.honnen@xxxxxx <
> xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> 
> > On 26.07.2016 13:51, Costello, Roger L. costello@xxxxxxxxx wrote:
> >
> > I need an XPath expression which returns true if the string in <A> is
> >> between 1 and 10 characters in length, and false otherwise.
> >>
> >> For example, the XPath expression should return true on this XML:
> >>
> >>         <A>hi</A>
> >>
> >> Here's an inefficient XPath expression:
> >>
> >> (string-length(.) gt 0) and (string-length(.) le 10)
> >>
> >> It's inefficient because it computes the string length twice.
> >>
> >> Is there a more efficient XPath expression to solve this problem?
> >>
> >
> > Well, in XPath 3 you can use
> >
> >   let $l := string-length()
> >   return ($l gt 0 and $l le 10)