Subject: Re: [xsl] Xslt string Operation From: "Mailing Lists Mail daktapaal@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 24 Aug 2016 16:21:40 -0000 |
I meant <xsl:variable name="OutFileName" select=" substring-before($fileHref, tokenize($fileHref,'/')[last()] ) || $outDir || '/' || substring-before( tokenize($fileHref,'/')[last()] ,'.xml') || '-Formatted.xml'"/> I can also take tokenize($fileHref,'/')[last()] in a variable and use it in the string operation above. But is there a better way ? On Aug 24, 2016 12:16 PM, "Mailing Lists Mail daktapaal@xxxxxxxxx" < xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > Dear all, > I have the following two params > <xsl:param name = bfileHrefb select = b bP:/developers/perf/bigPayload.xmlb b/> > <xsl:param name="outDir" select="'outDir'"/> > > I want OutFileName to be : bP:/developers/perf/outDir/bigPayload-Formatted.xmlb > > Is there a better way to do this than what I did? > <xsl:variable name="OutFileName" select=" substring-before($fileHref, tokenize($fileHref,'/')[last() -1 ] ) || $outDir || '/' || substring-before( tokenize($fileHref,'/')[last()] ,'.xml') || '-Formatted.xml'"/> > > thanks. > Dt > > XSL-List info and archive > EasyUnsubscribe (by email)
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