Re: [xsl] Get the last consecutive matching element

Subject: Re: [xsl] Get the last consecutive matching element
From: "Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Fri, 26 Aug 2016 16:59:46 -0000
Something like this, perhaps:

     /*/*/*/ul/li[@status='new'][1]
                /following-sibling::*[self::li and
not(@status='new')][1]/preceding-sibling::li[1]"/>

On Fri, Aug 26, 2016 at 8:31 AM, Rick Quatro rick@xxxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> Hi All,
>
> Here is my XML file:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <topic>
>     <body>
>         <p>
>             <ul>
>                 <li status="new">1</li>
>                 <li status="new">2</li>
>                 <li status="new">3</li>
>                 <li>4</li>
>                 <li>5</li>
>                 <li status="new">6</li>
>             </ul>
>         </p>
>     </body>
> </topic>
>
> My context node is <li status="new">1</li>. I want to get the last
> consecutive following-sibling with the same status value. So, in this case,
> I want to find this one: <li status="new">3</li>. I don't want 6 because
> there are intervening elements between. I am using this
>
> following-sibling::*[1][@status='new']
>
> to get the next one, but I am wondering if there is a single XPath 1.0
> statement that will get me directly to 3 when the context node is 1. Thank
> you very much.
>
> Rick Quatro
> Carmen Publishing Inc.
> 585-366-4017
> rick@xxxxxxxxxxxxxxx
>
>
>
>
> 



-- 
Cheers,
Dimitre Novatchev
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