Subject: [xsl] sequential numbering with for-each From: "a kusa akusa8@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 30 Aug 2016 17:57:08 -0000 |
Hello: I have a situation where I need to iterate over an element twice and output sequential numbers. I have two input files: First XML file. foo occurrence is 1 to infinity <root> <foo type="f1"> <foo1>ok</foo1> <foo1>not ok</foo1> </foo> </root> Second XML file. tables can occur 1 to infinity. tab1 can also occur 1 to infinity. <root1> <table ttype="f1"> <tables> <tab1> Data1 </tab1> <tab1> Data2 </tab1> </tables> <tables> <tab1> ...... </tab1> <tab1> Data3</tab1> </tables> </table> </root1> The logic is: for each /root/foo[@type = @ttype from 'root1']/foo1 repeat tab1 Desired output: 1. Data1 - ok 2.Data1 - not ok 3.Data2 - ok 4.Data2 - not ok 5.Data3 -ok 6.Data3-not ok I am able to get the individual 'tab1' elements to repeat. But my sequential numbering label is off. If I use position() within for-each it resets for every call in the for-each loop. I get: 1. Data1 - ok 2.Data1 - not ok 1.Data2 - ok 2.Data2 - not ok 1.Data3 -ok 2.Data3-not ok Any ideas or suggestions on how to make this work will be appreciated.
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