Subject: [xsl] How to find out if Xml contains two or more equal element name value with xsl? From: "Rahul Singh rahulsinghindia15@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 7 Sep 2016 09:43:42 -0000 |
Hi, I have only one XML. and there <Nid> contains same data like 000817441. I want to throw an email for same data. How to find out if Xml contains two or more equal element name value with xsl? But my code is not responding *Below is XML:* <?xml version="1.0" encoding="UTF-8"?> <objects> <Contact> <Id>003j000001Cj6l8AAB</Id> <Nid>000817441</Nid> </Contact> <Contact> <Id>007j000001Cj6l8AAB</Id> <Nid>000817441</Nid> </Contact> <Contact> <Id>003j700001Cj6l9AAB</Id> <Nid>001191237</Nid> </Contact> <Contact> <Id>003j000801Cj6lAAAR</Id> <Nid>010978087</Nid> </Contact> <Contact> <Id>003j000001Cj9l8AAB</Id> <Nid>000817441</Nid> </Contact> </objects> *Below in XSL:* <xsl:stylesheet version="2.0" xmlns:xsl=" http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" omit-xml-declaration="no"/> <xsl:strip-space elements="*"/> <xsl:template match="objects"> <xsl:if test="boolean(//objects/Contact[./Nid > preceding-sibling::node() or ./Nid > following-sibling::Nid])"> <Nid> <xsl:value-of select="Nid"/> </Nid> </xsl:if> </xsl:template> </xsl:stylesheet> *Expected output:* <Nid>000817441</Nid>
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