Subject: Re: [xsl] Image size with XSL? From: "Mark Wilson pubs@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sun, 18 Dec 2016 20:28:49 -0000 |
Hi John, I use the free version of Saxon 96 (but also have Oxygen, which may have some other processor). Will your citation work with that? (I am very much a novice with XSLT). Went to your citation and was pleased to see the ASN1 reference -- I developed several C++/ASN1/BER applications for Z30.50 back in the day (I am 77 now). I will look over the stuff and see if I can do anything with it. Thanks, Mark On 12/18/2016 1:14 PM, John Lumley john.lumley@xxxxxxxxxxxxxx wrote: > If your XSLT processor supports EXPath Binary (Saxon-PE/EE does ), > then you can use the technique illustrated at > http://expath.org/spec/binary#example%E2%80%93JPEG. > Alternatively if you can execute Java functions as extension > functions, then are quite a few possibilities through that route. > > John Lumley > > On 18 Dec 2016, at 19:54, Mark Wilson mark@xxxxxxxxxxxx > <mailto:mark@xxxxxxxxxxxx> <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx > <mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>> wrote: > >> I would like to add the placement-index to the XML data source >> programmatically. Is there a way to obtain the height or width of a >> jpeg image from the file itself (image.jpg, for instance) using XSLT? >> Or, can someone suggest another way to do this programmatically? > XSL-List info and archive <http://www.mulberrytech.com/xsl/xsl-list> > EasyUnsubscribe <-list/2754769> > (by email <>)
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