Subject: Re: [xsl] Question on translate() function From: "Syd Bauman s.bauman@xxxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Mon, 25 Sep 2017 17:42:01 -0000 |
Right. Use the same number of number signs in the 3rd parameter as you have chars you want replaced in the 2nd parameter. Reminder, in this case (OP wants every character in 2nd param replaced by number sign), it is better to have too many number signs in the 3rd param than too few. (Although I don't think anyone would argue that having the correct number of # is the right way to go.) Mike, or other internals guru -- I have always presumed that translate() is faster than replace().[1] I know that I, the mere XSLT programmer, am not supposed to worry my pretty little head about optimization unless I actually have a problem. And I know that if one of my students asked, that's what I would answer: "You have 1 MiB of XML data, and that computer on your lap would have been considered a supercomputer a mere two decades ago. Yes, A is probably more efficient than B, but the number of microseconds you save, even when added up over thousands of iterations of this transformation, will end up being less time than this conversation. Besides, we don't know what optimization the XSLT engine is (or is not) doing -- for all we know it might be better at optimizing B, even if un-optimized B is slower. So don't fret the speed unless something is running too slow." But I can't help it, sometimes -- I'd really like to know if translate() is significantly more efficient (computationally) than replace() or not. Notes ----- [1] Not sure why I have this prejudice. Perhaps because translate() was in XSLT1, but replace() was not; more likely because replace() uses regular expressions, which I imagine take quite a bit of computing; but most likely as a leftover from my IBM S360 Assembler days, when a translate was done in a single machine instruction. (Of course, it only operated on the 256 8-bit chars of EBCDIC, not on Unicode.) > translate($string ,'()''+-*$=' , '#') > > That means "replace '(' by '#', remove any occurrences of ')' or ' > or '+' or '-' or '*' or '$' or '=', and leave anything else > unchanged." > > If you want all the characters in the second argument to be > replaced by '#' characters then you need to write > > translate($string ,'()''+-*$=' , '########') > > Alternatively, use the replace() function.
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