Re: [xsl] XPath expression which expresses sequence-extended = (sequence, item)

Subject: Re: [xsl] XPath expression which expresses sequence-extended = (sequence, item)
From: "Costello, Roger L. costello@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 21 Nov 2017 19:08:41 -0000
David Carlisle wrote:

> why?

What I mean is that this expression:

$sequence-extended/item = ($sequence/item, $item)

returns false when $sequence is empty (and the other variables have the values
I described).

/Roger

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