Re: [xsl] Using saxon:parse on processing instructions

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 18.12.2017 21:18, Spencer Tickner spencertickner@xxxxxxxxx wrote:
> Hello and thanks in advance for the help. I'm scratching my head on 
> trying to convert a string of serialized xml in a processing instruction 
> back into XML.
>
> I'm restricted to XSLT 2.0 and am using Saxon 9.1. When I treat the 
> simply copy and past the xml into the stylesheet everything works (see 
> variable $s2), but when breaking the string out of the processing 
> instruction the elements remain serialized:
>
> input:
>
> <?xml version="1.0"?>
> <root xmlns:bcl="http://bcl";>
> <?pi a="&lt;bcl:e&gt;Test&lt;/bcl:e&gt;" ?>
> </root>

A PI does not contain parsed character data so your data is double escaped.

Does


	<xsl:template match="processing-instruction('pi')">
		<root xmlns:bcl="http://example.com/bcl";><xsl:value-of 
select="saxon:get-pseudo-attribute('a')" 
disable-output-escaping="yes"/></root>
	</xsl:template>
	

work with your version of Saxon?

With Saxon 9.7 PE that gives

	<root xmlns:bcl="http://example.com/bcl";><bcl:e>Test</bcl:e></root>