Re: [xsl] XPath to find duplicate elements

["Leo Studer leo.studer@xxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Dimitre, I am not sure whether I understand your two centsb&
For each node you read, you have to compare all following nodes. How would you
like to do that in the initial reading?

Yours
Leo


> On 5 Apr 2018, at 20:15, Dimitre Novatchev dnovatchev@xxxxxxxxx
<mailto:dnovatchev@xxxxxxxxx> <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx
<mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>> wrote:
>
> Just a thought on this.
>
> If we can implement deep-equal($n1, $n2)  as calculating some
> ValueIdentity (VI) for each of the nodes and returning
>
>     VI1 eq VI2 ...
>
> Then the VIs for each node can be calculated on the initial reading of
> the XML document (even in streaming mode) with almost no additional
> effort. If these VIs are made properties of the nodes, then we could
> just compare the VIs of the nodes and avoid any repeated zip-like
> comparison of the subtrees that are topped by these nodes. And this
> also seems more declarative/functional.
>
> Just my 2c.
>
> Cheers,
> Dimitre
>
>>>
>>> let $xml := <a>
>>>                 <b>
>>>                     <c>1</c>
>>>                     <d>1</d>
>>>                     <d>2</d>
>>>                 </b>
>>>                 <b>
>>>                     <c>2</c>
>>>                     <d>1</d>
>>>                     <d>3</d>
>>>                 </b>
>>>                 <b>
>>>                     <c>3</c>
>>>                     <d>2</d>
>>>                     <d>3</d>
>>>                 </b>
>>>                 <b>
>>>                     <c>3</c>
>>>                     <d>2</d>
>>>                     <d>3</d>
>>>                 </b>
>>>             </a>
>>>             return