Subject: Re: [xsl] Constructing a Map Using xsl:for-each-group From: "Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 25 May 2018 23:21:20 -0000 |
Your <map:entry> elements should be <xsl:map-entry>. Had me baffled for a bit. Michael Kay Saxonica > On 26 May 2018, at 00:06, Eliot Kimber ekimber@xxxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > I want to construct a map where the keys are attribute values and the entries contain the elements that exhibit those attribute values. The obvious way to do this is with for-each-group: > > <xsl:variable name="links-by-target-id" as="map(xs:string, element()*)"> > <xsl:map> > <xsl:for-each-group select="$docbook-links" group-by="@linkend"> > <map:entry key="{current-grouping-key()}"> > <xsl:sequence select="current-group()"/> > </map:entry> > </xsl:for-each-group> > </xsl:map> > </xsl:variable> > > However, using Saxon 9.8.0.8 from Oxygen I get this message: > > "Required item type of xsl:map sequence constructor is map(*); supplied value (xsl:for-each-group) has item type element(). The expression can succeed only if the supplied value is an empty sequence." > > The XSLT spec says that the contents of <xsl:map> is a sequence constructor, which for-each-group certainly is. > > Is this message legit? I don't see how it can be but maybe I'm missing a subtlety in the map instruction? > > Thanks, > > Eliot > -- > Eliot Kimber > http://contrext.com
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