Re: [xsl] XSLT1.0 distinct list of attributes across several nodes

Subject: Re: [xsl] XSLT1.0 distinct list of attributes across several nodes
From: "Mark Anderson mark.anderson@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Wed, 27 Jun 2018 21:51:51 -0000
Thanks David

Worked great!


a Segerdahl company
Mark Anderson
Director of ERP Systems
Phone: 847-419-3329
Mobile: 13125764332
Email: mark.anderson@xxxxxxxxx
www.sg360.com
-----Original Message-----
From: David Carlisle d.p.carlisle@xxxxxxxxx
[mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx]
Sent: Tuesday, June 26, 2018 4:47 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] XSLT1.0 distinct list of attributes across several nodes

actually I think you are filtering on non-empty content rather than non-empty
id so...



$ xsltproc.exe hop.xsl hop.xml
<?xml version="1.0"?>

   post_press 25  1, 2, 3, 5
   post_press 26  1, 2, 3, 6




from


<xsl:stylesheet version="1.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

 <xsl:key name="h" match="hopper[text()]"
      use="concat(ancestor::post_press_version/post_press_version_id,
           ':',
           @number)"/>

 <xsl:template match="order">
  <xsl:for-each select="post_press_version">
   post_press <xsl:value-of select="post_press_version_id"/>
   <xsl:text>  </xsl:text>
   <xsl:for-each select=".//hopper[text()]
             [generate-id(.)=
    generate-id(key('h',concat(ancestor::post_press_version/post_press_versio
n_id,
           ':',
           @number))[1])]">
    <xsl:if test="position()!=1">, </xsl:if>
    <xsl:value-of select="@number"/>
   </xsl:for-each>
  </xsl:for-each>
 </xsl:template>


</xsl:stylesheet>

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