[xsl] Re: [XSL-FO] Linebreaks on a page break (linefeed-treatment)

["Mathias Leclercq mathias.leclercq@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Hello guys,

So I did a recursive named template with the code below and the line-breaks
are effectively transformed.
I still had the problem though but because my empty blocks were in a
<fo:inline> node.
I removed the inline node and now it's working!
Thanks a lot for your help!

For further reference:

[XSLT 1.0] [XSL-FO] [FOP 1.0] Fix for line-feed issue on page-break with
different page layouts (margin left and right)

-   No <fo:block> inside <fo:inline>

-   Replace line-feed &#x000A; with &#x00A0;<fo:block/> with a recursive named
template

-   Remove linefeed-treatment="preserve" and
keep-together.within-page="always" attributes

<xsl:template name="gReplaceLineBreak">
        <xsl:param name="pString"/>
        <xsl:choose>
               <xsl:when test="substring-before($pString,'&#xA;')">
                       <xsl:value-of
select="substring-before($pString,'&#xA;')"/>&#x00A0;<fo:block/>
                       <xsl:call-template name="gReplaceLineBreak">
                               <xsl:with-param name="pString"
select="substring-after($pString,'&#xA;')"/>
                       </xsl:call-template>
               </xsl:when>
               <xsl:otherwise>
                       <xsl:value-of select="$pString"/>
               </xsl:otherwise>
        </xsl:choose>
</xsl:template>



From: Flynn, Peter <pflynn@xxxxxx>
Sent: Monday, July 2, 2018 10:01 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [XSL-FO] Linebreaks on a page break (linefeed-treatment)

On 2018-07-02 08:31:06+01:00 Mathias Leclercq
mathias.leclercq@xxxxxxxxx<mailto:mathias.leclercq@xxxxxxxxx> wrote:

Someone suggested me to replace linefeed characters in my text area with an
empty block &lt;fo:block&gt;&lt;/fo:block&gt;.

Problem is, I don't know what character to look for (xml is encoded in utf-8
on a windows machine).
The numeric character entity &#xa; matches a newline, so
replace(textArea,'&#xa;[&#xa;]*','&#xa;') will replace all multiple newlines
with a single newline.

If you are constrained to using XPath 1.0, you could write a recursive named
template to do the job, testing for two newlines each time, and replacing with
one, until no double newlines are left, then emitting an <fo:block/>

///Peter