Re: [xsl] Display the count of nodes and its descendent nodes in xslt

["Christophe Marchand cmarchand@xxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

First step to learn XSLT is to learn XPath. There is a wonderful tuto 
from Roger Costello here : http://www.xfront.com/xpath/

Your problem can be solved mainly with XPath, as Peter has shown.

Best regards,
Christophe


Le 18/10/2018 C  23:30, Peter Flynn peter@xxxxxxxxxxx a C)critB :
> On 18/10/18 20:21, kvsskishore kumar kvsskishorekumar@xxxxxxxxx wrote:
> > Hi,
> > Im newbie and started learning xslt on my own, I came to a part where I
> > have to show the node name along with their decsending nodes count under
> > it.
> Without knowing more about your application, what you seem to be looking
> for is (within a template, not shown):
>
> ...
>    <xsl:value-of select="name()"/>
>    <xsl:text> has </xsl:text>
>    <xsl:value-of select="count(descendant::node())"/>
>    <xsl:text> descendant nodes.</xsl:text>
> ...
>
> ///Peter