Subject: [xsl] Confusion with the results of starts-with() and a non-string arg From: "Bridger Dyson-Smith bdysonsmith@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 12 Dec 2018 21:09:57 -0000 |
Hi all - In the process of trying to illustrate something for a coworker, I stumbled across some behavior that has me Very Confused. I would expect the starts-with function to return 'false' when the second argument is not a string, but the opposite happens: it returns 'true'. Can someone please help me understand what's happening here? Is this a sort of type casting, or something else? Thank you in advance. Best, Bridger source.xml ``` <?xml version="1.0" encoding="UTF-8"?> <test> <my-string>This Is My String</my-string> </test> ``` test.xsl ``` <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0"> <xsl:output method="xml" indent="yes" encoding="UTF-8"/> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="my-string"> <xsl:if test="starts-with(.,true)"> <my-string-true> <xsl:value-of select="starts-with(.,true)"/> <xsl:text>###</xsl:text> <xsl:value-of select="starts-with(.,'no')"/> </my-string-true> </xsl:if> </xsl:template> </xsl:stylesheet> ```
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