Re: [xsl] bat file creation based on xsl /xml

["Syd Bauman s.bauman@xxxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Michele may have hit the nail on the head, here, but some other
issues are raised.

 0) I don't think the @version and @indent attributes of <xsl:output>
    make much sense when method=text. (And I'll ask that wiser folks
    than me post a correction if I'm wrong on that.)

 1) The OP's XSLT is not well-formed. (There is an extraneous end-tag
    for <xsl:variable> lying around.)

 2) I'm not 100% sure what `dir` does in Windows, but I'll bet it
    would list the files that end in '.xml'. This program also tries
    to *read* and *parse* those files. So whereas `dir` will happy
    list a file that is not really XML so long as it has a .xml
    extension, this program will entirely fail if any one of the
    files found in the same directory as the XSLT program ends in
    '.xml' but is not well-formed XML. (Which may, of course, be the
    desired behavior. In which case one might be better off using
    `xmlwf`. :-)

 3) This program spits out the URL of each selected file, not its
    name (or path & name). On my (GNU/Linux system running Saxon 9
    HE) that means that each file's output line will start with
    "file:". And it also has implications for character escaping
    (i.e., what happens if a space or solidus or whatever is in the
    file's name -- here you get %-sign escaping, but I doubt `dir`
    does that).

 4) This program reads in an input file, but then summarily ignores
    it when choosing the directory to list. I can't help but wonder
    if OP wants a list of the .xml files in the same directory as the
    XSLT program (which is what this program gives me when I run it
    w/ Saxon), or would prefer a list of the .xml files in the same
    directory as the input document.

=========
<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
  exclude-result-prefixes="#all">

  <xsl:output method="text" encoding="UTF-8"/>

  <xsl:template match="/">
    <xsl:text>&#x0A;----- XSLT program file's directory -----</xsl:text>
    <xsl:for-each select="collection('.?select=*.xml')">
      <xsl:text>&#10;</xsl:text>
      <xsl:value-of select="document-uri(.)"/>
    </xsl:for-each>
    <xsl:text>&#x0A;&#x0A;----- XML file's directory -----</xsl:text>
    <xsl:for-each select="collection( concat( replace( base-uri(/),
'/[^/]+$',''),'?select=*.xml'))">
      <xsl:text>&#10;</xsl:text>
      <xsl:value-of select="document-uri(.)"/>
    </xsl:for-each>
    <xsl:text>&#x0A;</xsl:text>
  </xsl:template>
</xsl:stylesheet>


> If I read this right, it looks like you just want to generate a
> list of the XML files in a directory, is that correct? If youbre in
> a windows enviroment the bdirb command will do what you want.