Re: [xsl] XSLT repetition constructs

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Am 07.03.2019 um 12:55 schrieb Michael Kay mike@xxxxxxxxxxxx:
> A good simple use case for fold-left() is to accumulate a running total, i.e. turn (1,2,3,4) into (1,3,6,10).

The example to simply compute the running total (e.g. map (1,2,3,4) to 
10) is in the spec with

B B  fold-left((1 to 4), 0, function($a, $b) { $a + $b})


But to map the whole sequence (1,2,3,4) with fold-left to a new sequence 
of (1,3,6,10) I am already struggling to express that in a compact way, is

fold-left(
B  (1 to 4),
B  (),
B  function ($a, $b) {B  $a, if (empty($a)) then $b else $b + $a[last()] }
)

a good way? Or can the third argument, the function be expressed in a 
more compact way?