Re: [xsl] Is there a way to use character-map to do replacements in a string ?

["Christophe Marchand cmarchand@xxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

I can survive with a global variable which is a map !

Thanks a lot !

Christophe

Le 19/03/2019 C  17:23, Martin Honnen martin.honnen@xxxxxx a C)critB :
> On 19.03.2019 16:15, Christophe Marchand cmarchand@xxxxxxxxxx wrote:
> > I have a variable :
> > <xsl:variable name="content" as="xs:string" select='EC'/>
> >
> > I want to transform special caracters according to a character-map
> > definition (I think it's much easier to maintain) :
> > B B  <xsl:character-map name="cm">
> > B B B B  <xsl:output-character character="E" string="oe"/>
> > B B B B  <xsl:output-character character="C" string="ss"/>
> > B B  </xsl:character-map>
> >
> > Something like
> > <xsl:variable name="escaped" as="xs:string"
> > select="escape-according-tocharacter-map($content, 'cm')"/>
> >
> > Is there a way to do it with XSLT 3.0 ?
>
>
> The serialize function from XPath 3 allows you to supply a character map
> but in XPath 3.1 map syntax
>
> serialize($content, map { 'method' : 'text', 'use-character-maps' : map
> { 'E' : 'oe', 'C' : 'ss' }})
>
> I am currently not sure there is a way to reference a map in the
> stylesheet, other than perhaps using
>
> B  map:join(document('')/*/xsl:character-map[@name =
> 'cm']/xsl:output-character/map-entry(@character, @string))
>
> instead of the hardcoded map { 'E' : 'oe', 'C' : 'ss' }}