Re: [xsl] Dynamic DTD declaration in output

["Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

In XSLT 2.0 you can do:

<xsl:template match="/">
  <xsl:result-document doctype-system="{$DefaultDTDPath}" method="xml"
encoding="utf-8">
    ....
  </xsl:result-document>
</xsl:template>

Michael Kay
Saxonica

> On 15 May 2019, at 06:45, Trevor Nicholls trevor@xxxxxxxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> Hi
>
> I've got a simple stylesheet which is executed as a pre-process when XML
documents are loaded into FrameMaker. At the moment the stylesheet includes
the line
>
>     <xsl:output doctype-system="/path/to/docs.dtd" method="xml"
encoding="UTF-8" />
>
> Because this stylesheet will be used by different users in several different
contexts, it would be brilliant if the path to the DTD could be parameterised.
I know the following is invalid but the purpose of this post is to ask if
there is any way of engineering an equivalent:
>
>     <xsl:param name="DefaultDTDPath" />
>     <xsl:output doctype-system="{$DefaultDTDPath}" method="xml"
encoding="UTF-8" />
>
> XSL version has to be 1.0 or 2.0.
>
> Thanks
> T
>
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