Subject: Aw: Re: [xsl] XSL | index-of() From: "Janine S. loderndesfeuer@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 27 Sep 2019 12:05:33 -0000 |
Hello everybody and thank you very much for your good answers. They help me to better understand XSL. I was also able to help myself with two for-each loops: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fn="http://www.w3.org/2005/xpath-functions" version="2.0" exclude-result-prefixes="#all"> <xsl:output method="xml" encoding="UTF-8" indent="yes"/> <xsl:template match="all"> <xsl:variable name="abbr" select="abbreviations/abbr"/> <all> <xsl:for-each select="//doc"> <xsl:variable name="actdoc" select="."/> <xsl:variable name="no" select="@no"/> <xsl:for-each select="$abbr"> <xsl:if test="fn:contains($actdoc, .)"> <doc no="{$no}"> <xsl:value-of select="."/> </doc> </xsl:if> </xsl:for-each> </xsl:for-each> </all> </xsl:template> </xsl:stylesheet> Many greetings Janine Gesendet: Freitag, 27. September 2019 um 12:46 Uhr Von: "Mukul Gandhi gandhi.mukul@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Betreff: Re: [xsl] XSL | index-of()Hi Janine, Here's the stylesheet that works, <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://stylesheet_fns" exclude-result-prefixes="xs fn" version="2.0"> <xsl:output method="xml" indent="yes"/> <xsl:template match="all"> <all> <xsl:for-each select="documents/doc[fn:isIncludeDoc(.)]"> <doc no="{@no}"><xsl:value-of select="substring-before(substring-after(., '('), ')')"/></doc> </xsl:for-each> </all> </xsl:template> <xsl:function name="fn:isIncludeDoc" as="xs:boolean"> <xsl:param name="doc" as="element(doc)"/> <xsl:sequence select="some $abbr in $doc/../../abbreviations/abbr satisfies contains($doc, concat('(', $abbr, ')'))"/> </xsl:function> </xsl:stylesheet> On Fri, Sep 27, 2019 at 2:37 PM Janine Lantzsch loderndesfeuer@xxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: Hello community, I am new in this list and hope very much that someone can help me or give me an input with which I can continue to work. I would like to use XSL to check whether a abbreviation from a list appears in a certain string of recurring elements. The abbreviation is always written in brackets. The source file looks like this (very simplified): <?xml version="1.0" encoding="UTF-8"?> <all> <abbreviations> <abbr>ABG</abbr> <abbr>AGI</abbr> <abbr>BBL</abbr> <abbr>ECK</abbr> </abbreviations> <documents> <doc no="1">The abbreviation (ABG) appears in this doc.</doc> <doc no="2">This doc has no shortcut.</doc> <doc no="3">An abbreviation (BBL).</doc> <doc no="4">And here (ECK).</doc> <doc no="5">And here again (ECK).</doc> </documents> </all> Only unfortunately I still have a bug somewhere with the index-of. Maybe the more experienced of you will see right away what's wrong with my code. I've been brooding since last night and can't find a solution :( <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fn="http://www.w3.org/2005/xpath-functions" version="2.0"> <xsl:output method="xml" encoding="UTF-8"/> <xsl:template match="all"> <xsl:variable name="abbr" select="abbreviations/abbr"/> <all> <xsl:for-each select="//doc"> <xsl:variable name="actdoc" select="."/> <xsl:if test="fn:contains($actdoc, fn:index-of($abbr, $actdoc))"> <doc> <xsl:attribute name="no"><xsl:value-of select="@no"/></xsl:attribute> <xsl:value-of select="$actdoc"/> </doc> </xsl:if> </xsl:for-each> </all> </xsl:template> </xsl:stylesheet> The output should look something like this: <all> <doc no="1">ABG</doc> <doc no="3">BBL</doc> <doc no="4">ECK</doc> <doc no="5">ECK</doc> </all> Thank you so much for your help! Many greetingsJanine S. -- Regards, Mukul GandhiXSL-List info and archiveEasyUnsubscribe (by email) XSL-List info and archiveEasyUnsubscribe (by email)
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