Subject: Re: [xsl] Separator for xsl:number @format From: "Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 23 Oct 2019 15:46:53 -0000 |
I don't think this can be achieved directly; you'll need to use some workaround. For example, generate the number as A#1 and then post-process to strip out the '#'. Alternatively, I sometimes find it works better not to use level=multiple, and instead use a series of calls to xsl:number for the individual levels. Michael Kay Saxonica > On 23 Oct 2019, at 15:41, Rick Quatro rick@xxxxxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > Hi, > > I am using xsl:number to format some sections. Here is my instruction: > > <xsl:number level="multiple" count="part|subpart" format="A1"/> > > I want my subparts to number A1, A2, A3, etc. Instead, I get A.A, A.B, A.C. > > <xsl:number level="multiple" count="part|subpart" format="A​1"/> > > If I add a zero-width space to the format, I get the desired result, but I want to know if this is necessary. I am using XSLT 2 and Saxon 9. Thank you very much. > > Rick > > Rick Quatro > Carmen Publishing Inc. > rick@xxxxxxxxxxxxxxx <mailto:rick@xxxxxxxxxxxxxxx> > 585-729-6746 > www.frameexpert.com/store/ <http://www.frameexpert.com/store/> > > > > > XSL-List info and archive <http://www.mulberrytech.com/xsl/xsl-list> > EasyUnsubscribe <http://lists.mulberrytech.com/unsub/xsl-list/293509> (by email <>)
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