Re: [xsl] LF and serialize()?

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Am 25.10.2019 um 15:08 schrieb Martin Honnen martin.honnen@xxxxxx:
> Am 25.10.2019 um 15:04 schrieb Birnbaum, David J djbpitt@xxxxxxxx:
> > When I run serialize() (in Saxon-HE 9.9.1.4J XSLT) over an XML
> > snippet, it does what I need, except that it replaces LF inside
> > attribute values with SP. This seems to be consistent with what I
> > read at https://www.w3.org/TR/REC-xml/#AVNormalize, and the
> > workaround described there (use a numerical character reference to LF
> > instead of the raw LF character) works. But Ibd like to avoid having
> > to specify in the XML something that I would prefer to manage during
> > the XSLT transformation, and I would also like to avoid
> > pre-processing the XML outside an XML environment and replacing the
> > LF with a numerical character reference there, before passing the
> > modified XML into the XSLT transformation.
> >
> >
> >
> > So: Would anyone happen to know of a way within just an XSLT
> > stylesheet to retain LF within an attribute value as distinct from SP
> > in the output of serialize()?
>
> What is an XML snippet? Are you sure it is the serialization that
> converts linefeeds to spaces or just the XML parsing (that is also what
> the spec you cite refers to)?


To illustrate, this XSLT snippet with XSLT 3 constructs some XML with an
attribute value containing line feeds and Saxon, when using the
"serialize" function, rightly then escapes them as numeric character
references, so

B B B  <xsl:variable name="xml-snippet">
B B B B B B B  <element>
B B B B B B B B B B B  <xsl:attribute name="att1">Line 1.
Line 2.
Line 3.</xsl:attribute>
B B B B B B B  </element>
B B B  </xsl:variable>
B B B  <xsl:value-of select="serialize($xml-snippet, map { 'method' :
'xml' })"/>


ouputs

<element att1="Line 1.&#xA;Line 2.&#xA;Line 3."/>


But of course serialize doesn't convert spaces any previous parsing step
has introduced back to line feeds.