Re: [xsl] Feedback on grouping solution

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 26.10.2019 19:03, Rick Quatro rick@xxxxxxxxxxxxxx wrote:

> I need to process the <step> child elements so that the <figure>
> elements are always on the "right" (even-numbered position) in the
> output. Immediate children of the <procedure> do not factor into the
> odd/even sequence.
>
> The first child of each group of adjacent <step> elements starts a new
> odd/even series. To ensure that the each <figure> is in an even-numbered
> position, I want to insert a <spacer> element where it is required.

> Here is my stylesheet. My basic question is: is there a better or more
> efficient way to do this? I really want to master grouping because it
> comes up in a lot of my tasks. Thank you for any input or criticism.
>
> <?xml version="1.0" encoding="UTF-8"?>
>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>
>      xmlns:xs="http://www.w3.org/2001/XMLSchema";
> exclude-result-prefixes="xs" version="2.0">
>
>      <xsl:output indent="yes"/>
>
>      <xsl:template match="/procedure">
>
>          <procedure>
>
>              <!-- Group the children of the procedure, keeping adjacent
> steps together. -->
>
>              <xsl:for-each-group select="child::*"
> group-adjacent="local-name(.)">
>
>                  <xsl:choose>
>
>                      <xsl:when test="current-group()[1][not(self::step)]">
>
>                          <!-- Single element. -->
>
>                          <xsl:apply-templates select="current-group()[1]"/>

I don't understand this part, what is supposed to happen with two (or
more) adjacent <note/><note/> or other non step elements? Do you want to
drop any but the first of them?