Subject: [xsl] How to read an XML file that is in a subfolder or sub-subfolder or sub-sub-subfolder or ...? From: "Costello, Roger L. costello@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 7 Apr 2020 13:05:47 -0000 |
Hi Folks, My XSLT program has a variable $filename which contains the name of an XML file. The XML file is in a folder named "files" or one of its subfolders or one of its sub-subfolders or one of its sub-sub-subfolders or ... In other words, it's somewhere in the tree of folders rooted at "files." I want to open the XML file (wherever it's located within "files") and read it into an XSLT variable. Is there a way to do this? /Roger
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