Re: [xsl] Nested for-each-group and current-group()

Subject: Re: [xsl] Nested for-each-group and current-group()
From: "Wendell Piez wapiez@xxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Mon, 11 May 2020 15:46:57 -0000

Alternatively, if you wish to continue using xsl:apply-templates
idiomatically and capture all nodes in traversal without the ungainly
"current-group()/node()", you could write

<xsl:for-each select="current-group()">

However, note that this will get you a demerit in certain automated
assessments of XSLT code "quality", which disparage any use of
for-each even for simple context switching. (Right Gerrit? ;-)

Cheers, Wendell

On Mon, May 11, 2020 at 10:44 AM Martin Honnen martin.honnen@xxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> Am 11.05.2020 um 16:34 schrieb Rick Quatro rick@xxxxxxxxxxxxxx:
> >
> > I am using nested xsl:for-each-group constructs but I don't get the
> > inner <ul> elements. I think I am incorrect in my use of
> > current-grouping-key() or current-group() on the inner group. Thanks in
> > advance.
> I think you need to process the child nodes of the current group with e.g.
>     current-group()/*
> in your inner grouping.

...Wendell Piez... ...wendell -at- nist -dot- gov...

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