Subject: Re: [xsl] Nested for-each-group and current-group()|
From: "Wendell Piez wapiez@xxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Mon, 11 May 2020 15:46:57 -0000
Hi, Alternatively, if you wish to continue using xsl:apply-templates idiomatically and capture all nodes in traversal without the ungainly "current-group()/node()", you could write <xsl:for-each select="current-group()"> <xsl:apply-templates/> </xsl:for-each> However, note that this will get you a demerit in certain automated assessments of XSLT code "quality", which disparage any use of for-each even for simple context switching. (Right Gerrit? ;-) Cheers, Wendell On Mon, May 11, 2020 at 10:44 AM Martin Honnen martin.honnen@xxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > Am 11.05.2020 um 16:34 schrieb Rick Quatro rick@xxxxxxxxxxxxxx: > > > > > I am using nested xsl:for-each-group constructs but I don't get the > > inner <ul> elements. I think I am incorrect in my use of > > current-grouping-key() or current-group() on the inner group. Thanks in > > advance. > > I think you need to process the child nodes of the current group with e.g. > current-group()/* > in your inner grouping. > > > > -- ...Wendell Piez... ...wendell -at- nist -dot- gov... ...wendellpiez.com... ...pellucidliterature.org... ...pausepress.org... ...github.com/wendellpiez... ...gitlab.coko.foundation/wendell...