Re: [xsl] XSLT program outputs a series of items, how to insertnewlines between each item?

["Roger L Costello costello@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Hi Martin,

I gave your suggestion a try (although, since I am running a Windows machine,
I used CRLF as the separator):

<xsl:value-of select="concat(@value, ' (', xs:annotation/xs:documentation,
')')" separator="&#xD;&#xA;"/>

Unfortunately, in the output the items are not separated by newlines. Any
thoughts on why that is?

/Roger

-----Original Message-----
From: Martin Honnen martin.honnen@xxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, June 25, 2020 9:17 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [EXT] Re: [xsl] XSLT program outputs a series of items, how to
insertnewlines between each item?


On 25.06.2020 15:11, Roger L Costello costello@xxxxxxxxx wrote:
> Hi Folks,
>
> My XSLT program has a loop. Each iteration outputs an item. I want each item
on a new line. The following works. Is there a better way to insert newlines
than by using xsl:text with the end tag on the next line?  /Roger
>
> <xsl:output method="text" />
>
> <xsl:template match="/">
>      <xsl:for-each select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration">
>          <xsl:value-of select="concat(@value, ' (',
xs:annotation/xs:documentation, ')')/>
> <xsl:text>
> </xsl:text>
>      </xsl:for-each>
> </xsl:template>


I would use xsl:value-of separator


<xsl:value-of select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration/concat(@value, ' (',
xs:annotation/xs:documentation, ')')" separator="&#10;"/>