Subject: Re: [xsl] XSLT program outputs a series of items, how toinsertnewlines between each item? From: "Roger L Costello costello@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 25 Jun 2020 13:37:44 -0000 |
> My suggestion is to replace the whole > for-each with the single value-of Oh my! That is wicked cool! Thanks Martin! /Roger -----Original Message----- From: Martin Honnen martin.honnen@xxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Sent: Thursday, June 25, 2020 9:27 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [EXT] Re: [xsl] XSLT program outputs a series of items, how toinsertnewlines between each item? On 25.06.2020 15:25, Roger L Costello costello@xxxxxxxxx wrote: > Hi Martin, > > > > I gave your suggestion a try (although, since I am running a Windows machine, I used CRLF as the separator): > > > > <xsl:value-of select="concat(@value, ' (', xs:annotation/xs:documentation, ')')" separator="
"/> > > > > Unfortunately, in the output the items are not separated by newlines. Any thoughts on why that is? > My suggestion is to replace the whole for-each with the single value-of I posted. > > > > -----Original Message----- > > From: Martin Honnen martin.honnen@xxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> > > Sent: Thursday, June 25, 2020 9:17 AM > > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > > Subject: [EXT] Re: [xsl] XSLT program outputs a series of items, how to insertnewlines between each item? > > > > > > On 25.06.2020 15:11, Roger L Costello costello@xxxxxxxxx wrote: > >> Hi Folks, >> My XSLT program has a loop. Each iteration outputs an item. I want each item on a new line. The following works. Is there a better way to insert newlines than by using xsl:text with the end tag on the next line? /Roger >> <xsl:output method="text" /> >> <xsl:template match="/"> >> <xsl:for-each select="//xs:simpleType[@name eq 'DatumCode']//xs:enumeration"> >> <xsl:value-of select="concat(@value, ' (', xs:annotation/xs:documentation, ')')/> >> <xsl:text> >> </xsl:text> >> </xsl:for-each> >> </xsl:template> > > > > > I would use xsl:value-of separator > > > > > > <xsl:value-of select="//xs:simpleType[@name eq > > 'DatumCode']//xs:enumeration/concat(@value, ' (', > > xs:annotation/xs:documentation, ')')" separator=" "/>
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] XSLT program outputs a se, Martin Honnen martin | Thread | [xsl] Any difference between 1 div , Roger L Costello cos |
Re: [xsl] XSLT program outputs a se, Martin Honnen martin | Date | Re: [xsl] XSLT program outputs a se, Graham Heath graham. |
Month |