Re: [xsl] Form feed character () in decoded xs:base64Binary

["Imsieke, Gerrit, le-tex gerrit.imsieke@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

I was suggesting that you prepend <?xml version="1.1"?> to your 
stylesheet document, hoping that you are then able to apply translate(., 
'&#xc;', '') to the decoded string.

On 13.07.2020 20:26, Martynas JuseviD
ius martynas@xxxxxxxxxxxxx wrote:
> With xsl:output version="1.1", the form feed is not a problem - Saxon
> writes the decoded xs:base64Binary string without any replacements.
>
> However I'm getting weird parsing errors downstream in my RDF toolkit
> (which works fine with XML 1.0). I'll try to see what the problem is.
>
> On Mon, Jul 13, 2020 at 8:00 PM Imsieke, Gerrit, le-tex
> gerrit.imsieke@xxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
> wrote:
> > What happens if you use version="1.1" in the XML declaration (of the
> > stylesheet)?
> >
> > On 13.07.2020 19:54, Martynas JuseviD
ius martynas@xxxxxxxxxxxxx wrote:
> > > Hi,
> > >
> > > I'm transforming large JSON files with some email data using XSLT 3.0.
> > > They contain xs:base64Binary literals which I'm decoding using
> > > bin:decode-string() and want to include the decoded values in the
> > > output XML.
> > >
> > > The problem is that some of the decoded string values have illegal XML
> > > 1.0 characters in them, such as Form feed (&#xc;).
> > >
> > > I want to remove them but cannot find a way.
> > > I can't use translate(., '&#xc;', '') because the stylesheet would not
> > > be well-formed anymore.
> > > I can't even use replace(., codepoints-to-string(12), '') because I
> > > get this error (with Saxon 10.1 EE):
> > >
> > >       codepoints-to-string(): invalid XML character [xc]. Found while
> > > atomizing the second argument of fn:replace()
> > >
> > > Are there any native XSLT options here?
> > >
> > > Thanks.