Re: [xsl] How to store a sequence into an element ... andmaintainthe sequence inside the element?

Subject: Re: [xsl] How to store a sequence into an element ... andmaintainthe sequence inside the element?
From: "Dr. Roger L Costello costello@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Sun, 19 Jul 2020 22:20:56 -0000
Michael, upon further reflection I realized that what you are saying is to
replace this markup:

   <Document>
       <Greeting>My List</Greeting>
       <List><xsl:sequence select="$list" /></List>
       <Ending>The End</Ending>
   </Document>

with a map:

<xsl:variable name="Document" as="map(xs:string, item()*)">
    <xsl:map>
        <xsl:map-entry key="'Greeting'" select="('My List')"/>
        <xsl:map-entry key="'List'" select="(1,2,3)"/>
        <xsl:map-entry key="'Ending'" select="('The End')"/>
    </xsl:map>
</xsl:variable>

My application will process the map rather than markup. Neat!

Dimitre, I am trying to avoid the overhead of markup. In matrices I don't want
the overhead that markup incurs. Instead, I want plain old sequences. Liam
talked about this in a post last week.

/Roger

-----Original Message-----
From: Dr. Roger L Costello costello@xxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Sunday, July 19, 2020 5:26 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [EXT] Re: [xsl] How to store a sequence into an element ...
andmaintainthe sequence inside the element?

Hello Michael,

Ah, so I think what you are saying is that I could store the sequence in a map
and then overwrite the sequence that is in the map. Something like this:

<xsl:variable name="list" as="map(xs:string, xs:integer*)">
    <xsl:map>
        <xsl:map-entry key="'li'" select="(1,2,3)"/>
    </xsl:map>
</xsl:variable>
... do some processing and then update the list ...
<xsl:variable name="list" select="map:put($list, 'li', (4,1,5))"/>
... do some more processing and then update the list ...
<xsl:variable name="list" select="map:put($list, 'li', (9,9,0))"/>
... do some more processing and then update the list ...

Right?

/Roger

From: Michael Kay mike@xxxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Sunday, July 19, 2020 4:58 PM
To: xsl-list <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: [EXT] Re: [xsl] How to store a sequence into an element ... and
maintainthe sequence inside the element?

That's the point Liam was making last week - XML is very text-oriented. When
you add a list of numbers to a document it gets serialized as a string. As
Martin says, you can turn it back into a sequence of numbers by validating
against a list type defined in a schema. But that's very limiting, which is
why XSLT 3.0 introduced maps and arrays.

Michael Kay
Saxonica


On 19 Jul 2020, at 20:14, Dr. Roger L Costello mailto:costello@xxxxxxxxx
<mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

Hi Folks,

I created a sequence (1, 2, 3) as follows:

<xsl:variable name="list" select="(1, 2, 3)" as="xs:integer*" />

I checked that $list contains 3 integers:

<xsl:message>count($list) = <xsl:value-of
select="count($list)"/></xsl:message>

Sure enough, the output shows that there are 3 items:

count($list) = 3

Next, I want to store that sequence of integers in an element, along with
other elements:

<xsl:variable name="document" as="element(Document)">
   <Document>
       <Greeting>My List</Greeting>
       <List><xsl:sequence select="$list" /></List>
       <Ending>The End</Ending>
   </Document>
</xsl:variable>

Does the <List> element contain a sequence of 3 integers:

<xsl:message>count($document/List) = <xsl:value-of
select="count($document/List)"/></xsl:message>

Yikes! No it doesn't:

count($document/List) = 1

How to do what I want to do? That is, how to store the sequence of integers in
an element, along with other elements, such that I can pull the sequence out
of the element and immediately operate on the sequence? If that can't be done,
then what's the right way to do what I want to do?

Here is my XSLT program:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
   xmlns:xs="http://www.w3.org/2001/XMLSchema";
   version="3.0">

   <xsl:template match="/">
       <xsl:variable name="list" select="(1, 2, 3)" as="xs:integer*" />
       <xsl:message>count($list) = <xsl:value-of
select="count($list)"/></xsl:message>
       <xsl:variable name="document" as="element(Document)">
           <Document>
               <Greeting>My List</Greeting>
               <List><xsl:sequence select="$list" /></List>
               <Ending>The End</Ending>
           </Document>
       </xsl:variable>
       <xsl:message>count($document/List) = <xsl:value-of
select="count($document/List)"/></xsl:message>
   </xsl:template>
</xsl:stylesheet>

/Roger

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