Re: [xsl] building a mental model for the "current node" behavior

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 05.11.2020 22:13, David Carlisle d.p.carlisle@xxxxxxxxx wrote:
> On Thu, 5 Nov 2020 at 14:46, Martin Honnen martin.honnen@xxxxxx
> <mailto:martin.honnen@xxxxxx> <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx
> <mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>> wrote:
>
>     Am 05.11.2020 um 15:11 schrieb Chris Papademetrious
>     christopher.papademetrious@xxxxxxxxxxxx
>     <mailto:christopher.papademetrious@xxxxxxxxxxxx>:

>      > As a novice, I get confused remembering when the current node
>      > does/doesnbt change. Therebs also this, which Ibm trying to
grasp:
>      >
>      > https://www.w3.org/TR/xslt-30/#func-current
>     <https://www.w3.org/TR/xslt-30/#func-current>
>      >
>      > Whatbs a good mental model for remembering this?
>      >
>      > 2. Inside an <xsl:template> block, is there a function that
>     returns the
>      > current **template-matched** node?
>
>     That is what the
>      B  B current()
>     function does, I am currently not sure why you first cite it and then
>     seem to ask for another function doing the job of the current()
>     function.
>
>
> No Christopher was correct, there is no function that does what he asks,
> and you need to use a variable.
> current() is theB  node at the beginning of the xpath not the surrounding
> template.
>
> Given
>
> <xsl:template match="wibble">
>
> <xsl:for-each select=".//zzz">
>
> <xsl:value-of select=" something with current()"/>
>
>
>
> then current() is the zzz node, and wibble is not accessible unless you
> saved it in a variable before the for-each.

That's true, guess my only excuse is that I did eliminate pull
processing from my mental model long before Gerrit punished it with his
score :)