Re: [xsl] with XPath 1.0, select all following sibling elements of name "foo" up to the first non-"foo" element

["Wendell Piez wapiez@xxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Indeed, I was going to add that the "real" way to do this under 1.0 was
XSLT sibling recursion, but I forgot.

Thanks David!


On Thu, Feb 18, 2021 at 4:35 PM David Carlisle d.p.carlisle@xxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

>
> > I am facing an XPath problem
>
> The answers so far have answered the question asked, but I wonder if that
> is the wrong question.
>
> To select the consecutive sequence of foo elements in xpath 1 requires
> some kind of double pass over the list and quadratic behaviour in the
> number of elements in the list.
>
> However if (as appears the case) the question is in an XSLT context rather
> than pure Xpath, you can usually avoid selecting the elements in a single
> expression.
> this does a single pass over the list stopping at the first non-foo
> element so is linear complexity
>
> xpath is just used to select one element at a time, the logic of handling
> just foo elements is pushed to a specific XSLT mode that only handles foo
> and stops at anything else,
>
> Given
>
> <x>
>
>  <b>
>   <foo>1</foo>
>   <foo>2</foo>
>   <bar>x</bar>
>   <foo>3</foo>
>  </b>
>
>  <b>
>   <foo>4</foo>
>   <foo>5</foo>
>   <foo>6</foo>
>  </b>
>
>  <b>
>   <bar>y</bar>
>   <foo>7</foo>
>   <foo>8</foo>
>  </b>
>
> </x>
>
>
> this stylesheet
>
> <xsl:stylesheet version="1.0" xmlns:xsl="
> http://www.w3.org/1999/XSL/Transform";>
>
>  <xsl:template match="b">
>    <zzz>
>    <xsl:apply-templates mode="onlyfoo" select="*[1]"/>
>    </zzz>
>  </xsl:template>
>
>  <xsl:template mode="onlyfoo" match="*"/>
>
>  <xsl:template mode="onlyfoo" match="foo">
>   <xsl:copy-of select="."/>
>   <xsl:apply-templates mode="onlyfoo" select="following-sibling::*[1]"/>
>  </xsl:template>
>
> </xsl:stylesheet>
>
>
> produces
>
>
>  <zzz><foo>1</foo><foo>2</foo></zzz>
>
>  <zzz><foo>4</foo><foo>5</foo><foo>6</foo></zzz>
>
>  <zzz/>
>
>
>
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