Re: [xsl] position() > 1 not working

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 05.03.2021 20:22, Michele R Combs mrrothen@xxxxxxx wrote:

> Ah.B  Ok, so if I understand correctly, I need to change the variable
> assignment to grab the position of the <DATA> element within the parent
> <ROW>, rather than within the for-each?B  How would I do that?


I think what David tries to say is that you want e.g.
  ../../fmp:COL[3]/fmp:DATA[$parent-position + 1]
instead of
  ../../fmp:COL[3]/fmp:DATA[$parent-position]

(and the same for the other values.)

Or you would need to use
  ../../fmp:COL[3]/fmp:DATA[position() >  1][$parent-position]
  ../../fmp:COL[4]/fmp:DATA[position() >  1][$parent-position]
  ../../fmp:COL[5]/fmp:DATA[position() >  1][$parent-position]
and so on to work in the same range your for-each works with.



> there are 4 DATA children so
>
> <xsl:for-each select="fmp:COL[3]/fmp:DATA[position() > 1]">
>
> selects the 2nd, 3rd andB  4th
>
> the scope of that position() is just that step of the xpath, within the
> body of the for-each, position() counts the selected items
>
> so as there are three items selected position() as stored in
> $parent-positionB  will have values 1,2,3 which is one less than you
> expected.