Re: [xsl] XQuery/XPath 3.1: Node List to Node Set ("distinct nodes")

Subject: Re: [xsl] XQuery/XPath 3.1: Node List to Node Set ("distinct nodes")
From: "Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 28 Dec 2021 21:56:08 -0000
You might consider

$nodes | ()

a bit more intuitive.

Michael Kay
Saxonica

> On 28 Dec 2021, at 19:23, Eliot Kimber eliot.kimber@xxxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> Hmph.
>
> That is certainly much more efficient p
 but is not necessarily obvious
(at least not to me).
>
> Thanks!
>
> E.
> _____________________________________________
>
> Eliot Kimber
> Sr Staff Content Engineer
> O: 512 554 9368
> M: 512 554 9368
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> From: Martin Honnen martin.honnen@xxxxxx <mailto:martin.honnen@xxxxxx>
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx
<mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>>
> Date: Tuesday, December 28, 2021 at 1:15 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx <mailto:xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
<xsl-list@xxxxxxxxxxxxxxxxxxxxxx <mailto:xsl-list@xxxxxxxxxxxxxxxxxxxxxx>>
> Subject: Re: [xsl] XQuery/XPath 3.1: Node List to Node Set ("distinct
nodes")
>
> [External Email]
>
>
> On 28.12.2021 20:10, Eliot Kimber eliot.kimber@xxxxxxxxxxxxxx
<mailto:eliot.kimber@xxxxxxxxxxxxxx> wrote:
> > I couldnbt find an answer in my google and markmail searching so I
> > thought Ibd ask here:
> >
> > Given an arbitrary list of nodes that may contain duplicates, what is
> > the most efficient way to reduce the node list to a set?
> >
> > The solution I came up with is a recursive function:
> >
> > (:
> >
> > Get the unique nodes from the supplied sequence
> >
> > @param nodes The sequence of nodes to evaluate
> >
> > @return A sequence of nodes such that each node in $nodes exists exactly
> > once.
> >
> > :)
> >
> > declare function dutils:distinctNodes($nodes as node()*) as node()* {
> >
> >    dutils:_getDistinctNodes($nodes, ())
> >
> > };
> >
> > declare function dutils:_getDistinctNodes($nodes as node()*, $resultList
> > as node()*) as node()* {
> >
> >    if (exists($nodes))
> >
> >    then
> >
> >    let $node := head($nodes)
> >
> >    return dutils:_getDistinctNodes(tail($nodes), ($resultList | $node))
> >
> >    else $resultList
> >
> > };
> >
> > Which works but I feel like Ibm missing some obvious way to do this
more
> > directly, but Ibm not seeing it.
> >
> > Am I missing a better solution?
>
> $nodes/.
>
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