[xsl] XPath equivalent to xsl:apply-templates?

["Roger L Costello costello@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Hi Folks,

I have inserted XPath code into an XML document, e.g.,

   <identifier>$ARPT_row/ICAO</identifier>

I wrote some code that extracts the XPath code and generates an XSLT
template:

    <xsl:template match="airports/airport/identifier">
        <xsl:param name="ARPT_row" tunnel="yes"/>
        <identifier>
            <xsl:value-of select="$ARPT_row/ICAO"/>
        </identifier>
    </xsl:template>

In some cases, I want to generate an XSLT template that has an
xsl:apply-templates, e.g.,

    <xsl:template match="airports">
        <xsl:param name="ARPT_row" tunnel="yes"/>
        <airports>
            <xsl:for-each select="$ARPT.XML/ARPT/row">
                <xsl:apply-templates select="current()/*">
                    <xsl:with-param name="ARPT_row" tunnel="yes" select="."/>
                </xsl:apply-templates>
            </xsl:for-each>
        </airports>
    </xsl:template>

What XPath code to put in the XML document <airports> element:

   <airports>???</airports>

The xsl:for-each can be replaced with the XPath "for" statement:

   <airports>for $i in $ARPT.XML/ARPT/row return ???</airports>

Do you have suggestions for an XPath that results in generating
xsl:apply-templates?

Is there an XPath equivalent to xsl:apply-templates? (Not sure if that
question makes sense)

[As I recall Dimitre is working to show how every construct in XSLT can be
represented in XPath. Okay, Dimitre, what's the XPath equivalent of
xsl:apply-templates?]

/Roger