Re: [xsl] Is it possible to use replace with an variable for entities?

["Bauman, Syd s.bauman@xxxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Hi Torsten!

I am not entirely sure I understand what you are trying to do here (it is
kinda late in my time zone :-), but I wonder if

replace( $value, '\\u(\d{4})', concat('&#', $1,, ';') )

would do the trick?
________________________________

I need to replace Unicode references (encoded in RTF) with entities via XSLT.

My replace command would look like these for example:

replace($value, '\\u7936', 'a<')
replace($value, '\\u183 \\\^b7', 'B7')

Now I want to avoid to have x-times (nested?) replaces for each character, but
would like to use a variable like this:

replace($value, '\\u(\d{4})', '&#$1;')
replace($value, '\\u(\d{3}) \\\^[0-9a-z]{2}', '&#$1;')

This, unfortunately, throws an error, as '&#$1;' is no valid entity
declaration.

Additionally, my parser doesn't allow to use map:keys($rtfEncodingMap).

Is there a workaround or a solution I might have missed?