Re: [xsl] XPath expression to convert XSD enumerations into a regex, longest value first

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 07.07.2022 19:02, Roger L Costello costello@xxxxxxxxx wrote:
> I have an XSD simpleType with enumeration values:
>
> <xsd:simpleType name="RunwayLightingType">
>    <xsd:restriction base="xsd:string">
>     <xsd:enumeration value="1"/>
>     <xsd:enumeration value="2"/>
>     <xsd:enumeration value="3"/>
>     <xsd:enumeration value="4"/>
>     <xsd:enumeration value="5"/>
>     <xsd:enumeration value="6"/>
>     <xsd:enumeration value="7"/>
>     <xsd:enumeration value="8"/>
>     <xsd:enumeration value="9"/>
>     <xsd:enumeration value="10"/>
>     <xsd:enumeration value="11"/>
>     <xsd:enumeration value="12"/>
>    </xsd:restriction>
>   </xsd:simpleType>
>
> I want to turn the values into a regex such that the longest value (not the
biggest value, the string longest value) is listed first:
> 12|11|10|9|8|7|6|5|4|3|2|1
>
> Seems like a simple problem, right? Should have a simple solution, right?
>
> Well, I devised a solution, but it sure ain't simple.
>
> string-join(for $i in reverse(sort(xs:restriction/xs:enumeration, (),
function($enum) {string-length($enum/@value )})) return $i/@value, '|')
> Is there is a simpler XPath expression to solve this problem?
Is 12 longer than 11 or 10?



As for simpler, the ! and => operators are supposed to allow for more
compact and easier to read expressions.