Re: [xsl] XPath expression to convert XSD enumerations into aregex, longest value first

["Imsieke, Gerrit, le-tex gerrit.imsieke@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Wendell, don't be reckless. Be mindful of my diabetes. But yes, it's a 
tasty morsel.

On 08.07.2022 14:35, Wendell Piez wapiez@xxxxxxxxxxxxxxx wrote:
> Even sweeter and more sugary
>
> let $backward := function($s) { - string-length($s) }
> return /*/xs:restriction/xs:enumeration/@value => sort((), $backward) => 
> string-join('|')
>
> Not to everyone's taste, for sure.
>
> Cheers, Wendell
>
>
> On Fri, Jul 8, 2022 at 6:34 AM Martin Honnen martin.honnen@xxxxxx 
> <mailto:martin.honnen@xxxxxx> <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx 
> <mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>> wrote:
>
>     Am 08.07.2022 um 12:23 schrieb Roger L Costello costello@xxxxxxxxx
>     <mailto:costello@xxxxxxxxx>:
>      >> At this point we're stuck because the requirements aren't clear.
>      >> In the example, 12 appeared in the output before 11, but we
>      >> don't know why: there was nothing in the requirements
>      >> statement that said it should.
>      >
>      > The only requirement is for the longer strings to come first.
>      >
>      > So any of these results would be fine:
>      >
>      > 12|11|10|9|8|7|6|5|4|3|2|1
>      > 11|12|10|9|8|7|6|5|4|3|2|1
>      > 10|11|12|9|8|7|6|5|4|3|2|1
>      > 12|11|10|1|2|3|4|5|6|7|8|9
>      > ...
>      >
>      > What is the simplest XPath expression to achieve that result?
>
>     As I indicated earlier, if you know => as an operator you might consider
>     the following simpler:
>
>     xs:restriction/xs:enumeration/@value/string()
>     => sort((), function($s) { -string-length($s) })
>     => string-join('|')
>
>     But in the end its syntactic sugar.
>
>
>
>
> --
> ...Wendell Piez... ...wendell -at- nist -dot- gov...
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--
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