Subject: Re: [xsl] replacing <!DOCTYPE> with <?xml-model?> in XSLT From: "Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 27 Jul 2022 21:16:22 -0000 |
On 27.07.2022 23:07, Chris Papademetrious christopher.papademetrious@xxxxxxxxxxxx wrote: > > > Given the following XML input: > > <?xml version="1.0" encoding="UTF-8"?> > > <!DOCTYPE topic PUBLIC "-//OASIS//DTD DITA Topic//EN" "topic.dtd"> > > <topic id="topic"> > > B <title>My Topic</title> > > </topic> > > I would like to replace <!DOCTYPE> with <?xml-model?>. With the following: > > <!-- remove the <!DOCTYPE> (works!) --> > > <xsl:output doctype-system=""/> > > <!-- add the <?xml-model?> (does not work) --> > > <xsl:template match="/*"> > > B <xsl:processing-instruction > name="xml-model">href="urn:oasis:names:tc:dita:rng:topic.rng" > schematypens=http://relaxng.org/ns/structure/1.0</xsl:processing-instruction> > > B <xsl:next-match/> > > </xsl:template> > > the <!DOCTYPE> removal works but the <?xml-model?> addition does not. > Is there a trick to emitting a PI before the root element? > In which environment, what is the processor you are you trying? And what happens if it doesn't work, any error?
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