Subject: Re: [xsl] Member function? From: "Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 2 Aug 2022 15:48:04 -0000 |
> OK, I'll ask. xsl:variable name=x select= ?? if not document('') Just replace <d:sort_index name="my_sort"> <d:entry key="Jan" index="0"/> <d:entry key="Feb" index="1"/> ... </d:sort_index> <xsl:variable name="sort_index" select="document('')//d:sort_index"/> with <xsl:variable name="sort_index" as="element(d:sort_index)" > <d:sort_index name="my_sort"> <d:entry key="Jan" index="0"/> <d:entry key="Feb" index="1"/> ... </d:sort_index> </xsl:variable> > > > RTF solved a problem (in 1998?). I guess there was less experience > around at the time? > > regards > > > > > > -- > Dave Pawson > XSLT XSL-FO FAQ. > Docbook FAQ.
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