Re: [xsl] How can I match some elements with cross-referencing?

["Richard Kerry richard.kerry@xxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Thanks Martin.  I'll look at using keys.  I have previously heard of XSL keys
but never had any cause to study how to use them until this.

There seems to be a "mailto:"; that's crept into your reply (or been added by
my mail client).  I guess that's someone's mail system deciding that '@'
(intended to mean attribute) should have the meaning it has in email
addresses.

Richard.



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From: Martin Honnen martin.honnen@xxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: 16 August 2022 12:18
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: Re: [xsl] How can I match some elements with cross-referencing?


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Am 16.08.2022 um 13:09 schrieb Richard Kerry
richard.kerry@xxxxxxxx<mailto:richard.kerry@xxxxxxxx>:



I am putting together an XSL stylesheet to convert the format of some XML
files [1].  I have a situation where I think I need some sort of
cross-referencing within the file for setting the template matches, but I
dont know how I might achieve that.

By that I mean that there are elements, lets call them type A, which use a
regular expression in their match specs, and when found it is also necessary
to find some related elements, type B, and rewrite them (or delete them).

I would appreciate some advice on what sort of method to use for this.



I think I can see three ways I might approach this.

  1.  On finding the type A element, its action includes finding the B element
and rewriting it.  This ties all the processing to one template match.
  2.  Two separate templates.  One matches elements A and processes them.  The
other matches elements of type B and includes some kind of look-up of any
corresponding type A element.
  3.  Extra passes.  First pass to extract a list of names, and second pass to
use that in the match spec, if possible.



Im not sure whether the first of these is even possible.  It includes one
template match of an element rewriting another element entirely.  Thats not
XSLs usual model and I dont think it can be done, can it?



If the second option is the way to go, how should I go about defining the B
element match to include the cross reference, ie the search to establish
whether there is a corresponding A  element?

There is not a 1:1 correspondence between the two types.  Not all B elements
have a corresponding A element.



So, to make it more concrete, lets say we have some A elements like this:



<A name=n1.u>Contents of A[n1]</A>

<A name=n2.u>Contents of A[n2]</A>

<A name=n3.u>Contents of A[n3]</A>



And some B like this:



<B reference=n1.u>Contents of B[n1]</B>

<B reference=n2.u>Contents of B[n2]</B>

<B reference=n3.u>Contents of B[n3]</B>


Use a key e.g.

  <xsl:key name="a" match="A[matches(@name,
(.+).u)]"<mailto:A[matches(@name,(.+).u)]> use="@name"/>


and then e.g.

  <xsl:template match="B[key('a', @reference)]"/>



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