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Subject: Re: [xsl] Filtering, xslt 2.0 From: "Dave Pawson dave.pawson@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Mon, 31 Oct 2022 16:35:02 -0000 |
<grin/> Not yet (will I ever be?) familiar with xslt 3.0
On Mon, 31 Oct 2022 at 16:22, Martin Honnen martin.honnen@xxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
>
> Am 10/31/2022 um 5:16 PM schrieb Dave Pawson dave.pawson@xxxxxxxxx:
> > Input xml contains
> > <data>
> > ...
> > <membership>....</membership>
> > </data>
> > where membership can be one of a b c d
> >
> > cmd line param
> > membership=a
> > could be membership=a,b,c
> >
> > How to 'choose' only those matching the param values?
> > <xsl:template match="data">
> > <xsl:if test="$membership =./membership">
> > <xsl:message>
> > <xsl:value-of select='membership_type'/>
> > </xsl:message>
> > <xsl:apply-templates/>
> > </xsl:if>
> > ..
> >
> >
> > How to pass a list, and then check for membership
> > of that list, one or more times?
>
> I see two options, pass in a single string like you do and tokenize e.g.
>
> tokenize($membership, ',') = membership
What's the command line then?
membership=a,b,c
or "a b c"
Saxon doesn't like that.
saxon ..... membership="R.A.O.B. Associate"
<xsl:if test="tokenize($membership',') =./membership">
Using Paid for saxon 9pe to produce op.xml
Unrecognized option: Associate
So space separated 'list' is wrong (somehow)
>
> or use an XPath expression for the parameter with e.g. (Saxon 9/10/11, I
> think)
>
> ?membership='a','b','c'
Where's this please Martin? In the match?
>
> (might need other/additional quotes, depending on the command shell), then
shell is bash
>
> $membership = membership
(Guess this is XSLT voodoo?)
why oh why did the WG go ...
regards
--
Dave Pawson
XSLT XSL-FO FAQ.
Docbook FAQ.
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