|
Subject: [xsl] XPath expression that returns a sequence of pairs? From: "Roger L Costello costello@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 17 Jan 2023 20:08:06 -0000 |
Hi Folks,
I have this XML document:
<Track-History>
<Track-ID>XYZ</Track-ID>
<Observation>
<Target-Latitude>10</Target-Latitude>
<Target-Longitude>20</Target-Longitude>
<Observer-Latitude>40</Observer-Latitude>
<Observer-Longitude>50</Observer-Longitude>
</Observation>
<Observation>
<Target-Latitude>15</Target-Latitude>
<Target-Longitude>25</Target-Longitude>
<Observer-Latitude>40</Observer-Latitude>
<Observer-Longitude>50</Observer-Longitude>
</Observation>
</Track-History>
I want an XPath expression that returns a sequence of (Target-Latitude,
Target-Longitude) pairs; i.e., a pair for each <Observation> element. For the
XML document shown above, the XPath should return this sequence:
(10,20), (15,25)
A count of the number of items in the sequence should yield: 2
The following XPath is not correct:
for $i in //Observation return ($i/Target-Latitude, $i/Target-Longitude)
A count of the number of items returned by that XPath yields: 4
Is there an XPath to do what I seek?
/Roger
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| [xsl] [ANN] Saxon 12.0, Michael Kay michaelk | Thread | [xsl] Re: XPath expression that ret, Chris Papademetrious |
| [xsl] [ANN] Saxon 12.0, Michael Kay michaelk | Date | [xsl] Re: XPath expression that ret, Chris Papademetrious |
| Month |