Subject: Re: [xsl] A beautiful way to populate a variable with N blanks? From: "Imsieke, Gerrit, le-tex gerrit.imsieke@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 24 Feb 2023 15:11:56 -0000 |
Hi Makita-san,
That is the form I was about to post too. Martin's suggestion is a novel use of the "!" operator, but my OCD seems to not like generating data that is never meaningfully used. Although longer, I feel the "for" loop's intent is a bit easier for future novices to follow.
That being said, I still enjoy seeing clever uses of the "!" operator!
- Chris
-----Original Message-----
From: Toshihiko Makita tmakita@xxxxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Friday, February 24, 2023 9:59 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] A beautiful way to populate a variable with N blanks?
How about the following?
<xsl:variable name="blanks" as="xs:string" select="string-join(for $i in
1 to $N return (' '), '')"/>
On 2/24/2023 11:44 PM, Roger L Costello costello@xxxxxxxxx wrote:
Hi Folks,
$N contains an integer.
$blanks is a string variable. The string is to consist of $N blanks (space characters).
Below is one way to populate $blanks. It's an awful solution. Is there a beautiful (simple) solution?
<xsl:variable name="tmp" as="xs:string+">
<xsl:sequence select="''" />
<xsl:sequence select="for $i in 1 to $N return (' ')"/>
</xsl:variable>
<xsl:variable name="blanks" as="xs:string">
<xsl:value-of select="$tmp" separator=""/> </xsl:variable>
Toshihiko Makita
Antenna House, Ina Branch.
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