Subject: [xsl] How to remove outer tag if present in XSLT From: "Matt Van Voorhies mvanvoorhies@xxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 17 Mar 2023 16:55:31 -0000 |
Hi folks, I have a hopefully simple question that I was unable to find a good answer for. Im trying to convert some code we have that manipulates an XML structure (transforming to HTML output) and move it into the XSLT transform. Problem: Given a specific XML tag, I need to remove the containing paragraph but only if its a single containing paragraph tag. Parsing using .NET Saxon 10.6 for transform. So for example, if I have the following XML structure <arbitrary-outer-tag-thats-valid> <p>Some content, probably a bunch of internal tags like H1, H2, LI, DIV, etc. </p> <p>More content, again, may have more stuff in it like an <p>Internal paragraph</p></p> <p>stuff3</p> </ arbitrary-outer-tag-thats-valid > Running through the transform would produce: <arbitrary-outer-tag-thats-valid> <p>Some content, probably a bunch of internal tags like H1, H2, LI, DIV, etc. </p> <p>More content, again, may have more stuff in it like an <p>Internal paragraph</p></p> <p>stuff3</p> </ arbitrary-outer-tag-thats-valid > Since there is not an outer/containing paragraph tag. However, if the input was <arbitrary-outer-tag-thats-valid> <p> <p>Some content, probably a bunch of internal tags like H1, H2, LI, DIV, etc. </p> <p>More content, again, may have more stuff in it like an <p>Internal paragraph</p></p> <p>stuff3</p> </p> </ arbitrary-outer-tag-thats-valid > Running through the transform would produce: <arbitrary-outer-tag-thats-valid> <p>Some content, probably a bunch of internal tags like H1, H2, LI, DIV, etc. </p> <p>More content, again, may have more stuff in it like an <p>Internal paragraph</p></p> <p>stuff3</p> </ arbitrary-outer-tag-thats-valid > Where the single, containing <p> tag was removed, but everything inside of it was retained exactly as it was. Could someone help? Thanks, Matt Van Voorhies mvanvoorhies@xxxxxxxxxxx
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