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Subject: [xsl] How to remove outer tag if present in XSLT From: "Matt Van Voorhies mvanvoorhies@xxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 17 Mar 2023 16:55:31 -0000 |
Hi folks,
I have a hopefully simple question that I was
unable to find a good answer for. Im trying to convert some code we have
that manipulates an XML structure (transforming to HTML output) and move it
into the XSLT transform.
Problem: Given a specific XML tag, I need to
remove the containing paragraph but only if its a single containing
paragraph tag. Parsing using .NET Saxon 10.6 for transform.
So for example, if I have the following XML
structure
<arbitrary-outer-tag-thats-valid>
<p>Some content, probably a bunch of
internal tags like H1, H2, LI, DIV, etc. </p>
<p>More content, again, may have more
stuff in it like an <p>Internal paragraph</p></p>
<p>stuff3</p>
</ arbitrary-outer-tag-thats-valid >
Running through the transform would produce:
<arbitrary-outer-tag-thats-valid>
<p>Some content, probably a bunch of
internal tags like H1, H2, LI, DIV, etc. </p>
<p>More content, again, may have more
stuff in it like an <p>Internal paragraph</p></p>
<p>stuff3</p>
</ arbitrary-outer-tag-thats-valid >
Since there is not an outer/containing paragraph tag.
However, if the input was
<arbitrary-outer-tag-thats-valid>
<p>
<p>Some content, probably a bunch of internal tags
like H1, H2, LI, DIV, etc. </p>
<p>More content, again, may have more stuff in it like
an <p>Internal paragraph</p></p>
<p>stuff3</p>
</p>
</ arbitrary-outer-tag-thats-valid >
Running through the transform would produce:
<arbitrary-outer-tag-thats-valid>
<p>Some content, probably a bunch of
internal tags like H1, H2, LI, DIV, etc. </p>
<p>More content, again, may have more
stuff in it like an <p>Internal paragraph</p></p>
<p>stuff3</p>
</ arbitrary-outer-tag-thats-valid >
Where the single, containing <p> tag was removed, but everything
inside of it was retained exactly as it was.
Could someone help?
Thanks,
Matt Van Voorhies
mvanvoorhies@xxxxxxxxxxx
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