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Subject: Re: [xsl] Seek an XPath expression that removes trailing spaces From: "Roger L Costello costello@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sat, 6 Jul 2024 13:09:45 -0000 |
Martin Honnen wrote:
Use 'replace' e.g.
Airport_Name => replace('\s*$', '')
Wow!
A couple minor tweaks are needed:
\s is more than just the space (x20) character. So, instead of \s I will use a
space.
When I executed the expression, I got this error message:
FORX0003 The regular expression must not be one that matches a zero-length
string
So, I need to use + instead of *
Here's the updated XPath:
replace(Airport_Name,' +$','')
Thank you Martin!
/Roger
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