Subject: Re: [xsl] Seek an XPath expression that removes trailing spaces From: "Roger L Costello costello@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sat, 6 Jul 2024 13:09:45 -0000 |
Martin Honnen wrote: Use 'replace' e.g. Airport_Name => replace('\s*$', '') Wow! A couple minor tweaks are needed: \s is more than just the space (x20) character. So, instead of \s I will use a space. When I executed the expression, I got this error message: FORX0003 The regular expression must not be one that matches a zero-length string So, I need to use + instead of * Here's the updated XPath: replace(Airport_Name,' +$','') Thank you Martin! /Roger
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