Re: [xsl] escape quotation marks in replace function

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

See https://www.w3.org/TR/xpath-31/#prod-xpath31-EscapeQuot, you should
be able to use two double quote characters "".

On 03/10/2024 21:15, Wolfhart Totschnig wolfhart.totschnig@xxxxxxxxxxx
wrote:
> On my end, it looks like the encoding of the smart quotation marks in
> the code got mixed up during the transmission of the email (namely,
> they seem to have been replaced by "\xE2"). I therefore attach a
> picture of what the code should look like in the email.
>
>
> On 10/3/24 15:51, Wolfhart Totschnig wolfhart.totschnig@xxxxxxxxxxx wrote:
>> Dear list,
>>
>> The following replace function replaces a /straight/ single quotation
>> mark (or apostrophe) with a /smart/ single quotation mark when it is
>> preceded by either a space or a /smart double/ quotation mark:
>>
>> <xsl:value-of select="replace(.,&#34;([
C"BB])'&#34;,&#34;$1C"BB&#34;)"/>
>>
>> I would like to add to this code such that it also replace the
>> straight single quotation mark when it is preceded by a /straight/
>> double quotation mark. What do I have to add between the brackets to
>> achieve this? Putting either ["] or [&#34;] produces an error since
>> both of these are used in the surrounding code.
>>
>> Thank you in advance for your help!
>> Wolfhart
>>
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